0=16x^2+60x-60

Solution for 0=16x^2+60x-60 equation:

0=16x^2+60x-60

We move all terms to the left:

0-(16x^2+60x-60)=0

We add all the numbers together, and all the variables

-(16x^2+60x-60)=0

We get rid of parentheses

-16x^2-60x+60=0

a = -16; b = -60; c = +60;
Δ = b2-4ac
Δ = -602-4·(-16)·60
Δ = 7440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7440}=\sqrt{16*465}=\sqrt{16}*\sqrt{465}=4\sqrt{465}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{465}}{2*-16}=\frac{60-4\sqrt{465}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{465}}{2*-16}=\frac{60+4\sqrt{465}}{-32}
$